Cow level Statistics For mathematics (Statistics) i had to do a final project, a statistical inference, i happened to do it on the cow level and whether or not the amount of scrolls in a tome affect the amount of cows in the level. Here is a 5 point summary + of each sample, base is the number u buy from the merchants or npc's in the tome, 1-4 scrolls, and full is 20 scrolls. Data Summary Full (20) Statistics:: Number: 20 Mean: 65.5 Standard Deviation: 6.4031 Minimum: 57 Quartile 1: 61 Median: 64 Quartile 3: 68.5 Maximum: 83 Base Statistics:: Number: 20 Mean: 55.1 Standard Deviation: 6.5767 Minimum: 44 Quartile 1: 51 Median: 54.5 Quartile 3: 58.5 Maximum: 74 I then conducted a two-sample T-Statistic test, to find the probability that my null (or base) hypothesis was true stating that the amount of cows created by both were equal against the probability that the amount of cows created by a full tome were greater. the probability of the null being correct was = 0.007%, the probability of the other being correct was = 99.993% Normally a statistic only has to be proven at the 95% confidence interval. so i concluded at the 99.993% confidence interval, which means that 99.993% of the time, at this difference in statistics this will represent the entire population, that having a full tome causes more cows to be present in the cow level, rejecting except for a 7 / 100,000 chance that the tome full and with base in it are equal. If you have any questions for me, my email is [email protected] or [email protected], my aim is Sven00100 my msn is [email protected] and my yahoo messenger screen name is [email protected]. Since i was not bias beforehand, and random game names were used, on USEAST ladder, this is a random sample, granted a simple random sample (SRS) is impossible since the games aren't pre-existing, but its next best, hopefully this defers disputes about this topic, as i've had many people telling me it both ways. Simply put, i am almost positive that a full tome is better used for more cows in the secret cow level. -Steven W.